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Carlos , just curious ... |
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AncientOne
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Topic: Carlos , just curious ...Posted: 1/27/06 at 7:50am |
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CB- You said in that other thread, "Ultimately what makes implements go far is power. Power is directly proportional to force, and inversely proportional to time." Or, power equals force times distance divided by time. I'm assuming that the distance is the length of the application of force on the implement, for example 8' for a gliding stone thrower. P=16lb*8ft/1sec=128 ft-lb/sec If this is correct, Craig's 55' open stone throw is the product of him improving or decreasing the amount of time in producing power? (or gaining velocity) because the force and distance remain constant? I was just noodling the idea, -KR |
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Borges
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Posted: 1/27/06 at 8:25am |
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I think that's a good first order explanation. In actuality though, it's more complicated than that because there are many other factors that would have to be considered. For instance, he isn't necessarily applying constant acceleration to the implement. (Does Craig have non-trivial jerk? Only his physics professor knows for sure.
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Cheers,
Carlos "Live free or die" |
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Borges
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Posted: 1/27/06 at 8:30am |
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Incidentally, you make an additional point. I left out C in the other post: C) Move the same weight over a longer distance in the same time. Which is why the snatch high pull is such a great exercise. |
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Cheers,
Carlos "Live free or die" |
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Geisler
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Posted: 1/27/06 at 12:23pm |
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No. You are somewhat misapplying the principle, the force in a stone throw isn't really applied until the stone is moved relative to the mass center of the body. The distance and time are measured from this point. Whether spinning or gliding, how far or fast you move up until that point will only factor into an inital velocity of the stone, the true accleration occurs when you plant and begin to heave it. That is the power you generate.
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Borges
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The Conrad Dobler of the Highland Games Joined: 8/30/04 Location: Jamaica Status: Offline Points: 2188 |
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Posted: 1/27/06 at 1:48pm |
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I disagree. If the thrower was not applying force then the stone would be in free fall. If the stone starts at a dead stop then by what magical physical phenomena does it end up moving all the way to the plant and gaining velocity? Incidentally, Kevin was not specific but I took it as understood that he was basically talking about the 'Braemar' part. Incidentally, I believe that a HUGE portion of the applied force (at least in the top throwers) comes from the legs while the stone is still tucked and hardly moving relative to the throwers center of mass. Very little is contributed by pushing with the arm. I believe that if I restrict Ryan to using only his arms, then even a hack like me could beat him in stone, every time.
Edited by Borges |
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Cheers,
Carlos "Live free or die" |
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